Both Arjun and Rahul went for jogging and stopped at a place where kids were playing on a slide as shown below

Two slides which are directed in the two opposite directions are combined with the vertical stairs in the midway between the two sliders.

The lengths of both the slides are same, the width of the slide is 1 m and the distance AC = 5 m. Find the distance AB.

10 m

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6 m

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5 m

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11 m

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Solution

The correct option is D
11 m

If you consider ΔACE and ΔBDF,
Given that, distances kids can slide on both the sliders are same.
AE = FB
EC = FD
∠ACE = ∠FDB = 90°(Since the stairs are vertical)
⇒ΔACE and ΔBDF are congruent using RHS congruence criterion
⇒AC = DB = 5 m

The distance AB = AC + CD + DB = 5m + 1m + 5m = 11 m

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