Both Arjun and Rahul went for jogging the next day and stopped at a place where kids were playing on a slide as shown below

Two slides which are directed in the two opposite directions are combined with the vertical stairs in the midway between the two sliders. The lengths of both the slides are same. Which of the following is/are true?

AE = FB

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EC = FD

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$∠$ ACE = $∠$ FDB = $90^{\circ}$

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EC = FB

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Solution

The correct options are
A
AE = FB

B
EC = FD

C
$∠$ ACE = $∠$ FDB = $90^{\circ}$

If you consider $Δ$ ACE and $Δ$ BDF,

Given that, distances kids can slide on both the sliders are same.

AE = FB

EC = FD (height of the stairs)

$∠$ ACE = $∠$ FDB = $90^{\circ}$ (Since the stairs are vertical)

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The correct options are A AE = FB B EC = FD C ∠ACE = ∠FDB = 90∘ If you consider ΔACE and ΔBDF, Given that, distances kids can slide on both the sliders are same. AE = FB EC = FD (height of the stairs) ∠ACE = ∠FDB = 90∘ (Since the stairs are vertical)