Question

Both $\left[Ni\right(CO{)}_4]$ and $\left[Ni\right(CN{)}_4{]}^{2-}$ are diamagnetic. The types of hybridisation of $Ni$ in these complexes are respectively:

• A. $s{p}^3,ds{p}^2$
• B. $s{P}^3,ds{P}^3$
• C. $ds{p}^2,s{p}^3$
• D. $ds{p}^2,ds{p}^2$

Answer 1

The correct option is A $s{p}^3,ds{p}^2$

$[NiC{l}_4{]}^{2-}$
$N{i}^{2+}=3d^8,4s^{0}4p^0$
In this complex, Cl is a weak ligand which does not pair the electrons. Therefore, two unpaired electrons are present in 3d-orbital. hence , $[NiC{l}_4{]}^{2-}$ is paramagnetic in nature.