Question

Both the blocks shown here of mass m and are moving with constant velocity in direction shown in resistive medium which exerts equal constant force on both blocks in direction opposite to the velocity. The tension in the string connecting both of them will be: ( Neglect friction)

• A. mg
• B. mg/2
• C. mg/3
• D. mg/4

Answer 1

The correct option is B mg/2

Given both the block is moving with constant velocity .
Applying the law of motion on the block lying on the table will give,
$T-F=0$ , where F is the resistive force
and on the other block will give,
$m\times g-T-F=0$
Solving both gives us, $T=(m\times g)/2$