Both the diodes used in the circuit shown are assumed to be ideal and have negligible resistance, when these are forward biased. Built-in potential in each diode is $0.7 V$ . For the input voltages shown in the figure, the voltage (in Volts) at point $A$ is .

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Solution

The diode on the right-hand side is reversed biased, while the one on left-hand side is forward biased.

Hence, voltage at $A$ ,

$V_{A} = 12.7 - 0.7 = 12 volts$

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Similar questions

The diodes D_{1} and D_{2} are non-ideal with cut-in voltages of 0.7 V and forward resistance r_{f} = 0 Ω and r_{r e v} = \infty . The Zener diode D_{z} has forward voltage drop of 0.7 V and a Zener voltage of 5 V. If an input sine wave of maximum peak amplitude of 10 V is applied at V_{i n}, then the transfer characteristic of the circuit can be represented as

D_{1}

D_{2}

200 V

R

R

R

V_{A}

V_{r} = 0.7 V

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