Question

Boyle's law may be expressed as $(dP/dV{)}_T=-K/V^2$
If true enter 1 else 0

• A. 1

Answer 1

The correct option is A 1
Boyle's law It states "at a constant temperature (T), the pressure (P) of a given mass (or moles, n) of any gas varies inversely with the volume (V)". Pressure (P) and volume (V) of gases.
$P\propto \frac{1}{V}\therefore {\left[\frac{\partial P}{\partial V}\right]}_T=-K/V^2$