Boyle's law may be expressed as $(d P / d V)_{T} = K / V$
If true enter 1 else 0.
0

Open in App

Solution

The correct option is A 0
Boyle's law It states "at a constant temperature (T), the pressure (P) of a given mass (or moles, n) of any gas varies inversely with the volume (V)". Pressure (P) and volume (V) of gases.
$P \propto \frac{1}{V} ∴ {[\frac{\partial P}{\partial V}]}_{T} = - K / V^{2}$

Suggest Corrections

Similar questions

(d P / d V)_{T} = - K / V^{2}

Boyle's law may be represented as

1.[dp/dv]T=K/V

2.[dp/dv]T=-K/V

3.[dp/dv]T=-K/V

4.[dp/dv]T=K/V^2

K = c o n s t a n t

Join BYJU'S Learning Program