a submarine produces sound that is detected by another submarine 45km away. how much time sound is taking to reach another submarine? (the speed of sound in water is 1500m/s)

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Solution

Dear student,
$T h e f i r s t s u b m a r i n e w i l l c r e a t e a s o u n d a n d t h a t w i l l b e h e a r d b y t h e 2 n d s u b m a r i n e . s o t h e d i s \tan c e t r a v e l l e d b y t h e s o u n d = d = 45 k m = 45, 000 m v e l o c i t y o f s o u n d i n w a t e r = V = 1500 m / s t i m e r e q u i r e d = t = ? a s, v e l o c i t y = \frac{d i s \tan c e}{t i m e} \Rightarrow t i m e = \frac{d i s \tan c e}{v e l o c i t y} = \frac{45000}{1500} = 30 s e c = 0.5 m i n s o t i m e r e q u i r e d b y t h e s o u n d t o r e a c h a n o t h e r s u b m a r i n e = 30 s e c$

Regards,

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