Question

Calculate the number of atoms and molecules in 124 grams of phosphorous and P4 respectively.

Answer 1

1. Number of moles of P₄ = $\frac{Givenweight}{Molecularweight}=\frac{124g}{124g/mol}=1mol$

Number of moles of P = $\frac{Givenweight}{Moleularweight}=\frac{124g}{31g/mol}=4moles$

2. Number of atoms in 1 mole of P = $6.023\times {10}^{23}atoms$
Number of atoms in 4 moles of P = $4\times 6.023\times {10}^{23}=24.092\times {10}^{23}$

3. Number of molecules in 1 mole P₄ = $6.023\times {10}^{23}molecules$
Number of atoms in 1 molecule of P₄ = 4
Number of atoms in 1 mole of P₄ = 24.092 $\times {10}^{23}atoms$