Q. A garden is 40 m by 30 m. It has 2.5 m wide flower bed all around outside it. There is also a 2.5 m wide grassy path all around the flower bed. Find the area of the flower bed and grassy path respectively.

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Solution

Dear student,

$L e n g t h o f g a r d e n, l = 40 m B r e a d t h o f g a r d e n, b = 30 m W h e n g a r d e n s u r r o u n d e d b y f l o w e r b e d o u t s i d e N e w l e n g t h o f g a r d e n, l' = 40 + 2.5 + 2.5 = 40 + 5 = 45 m N e w b r e a d t h o f g a r d e n, b' = 30 + 2.5 + 2.5 = 30 + 5 = 35 m A r e a o f f l o w e r b e d = A r e a o f g a r d e n w h e n s u r r o u n d e d b y f l o w e r b e d - A r e a o f g a r d e n = (45 \times 35) - (40 \times 30) . . . [a r e a o f r e c \tan g l e = l e n g t h \times b r e a d t h] = 1575 - 1200 = 375 m^{2} N o w, l e n g t h o f g r a s s y p a t h = 45 + 2.5 + 2.5 = 50 m b r e a d t h o f g r a s s y p a t h = 35 + 2.5 + 2.5 = 40 m A r e a o f g r a s s y p a t h = A r e a o f g a r d e n i n c l u d i n g g r a s s y p a t h - A r e a o f g r a s s y p a t h = (50 \times 40) - (45 \times 35) = 2000 - 1575 = 1425 m^{2}$

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