Q. Force between two identical short bar magnets whose centres are r metre apart is 4.8 N when their axes are in the same line. If the separation is increased to 2r metre, the force between them is reduced to

0.3 N

0.6 N

2.4 N

1.2 N

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Solution

Dear Student,

$f o r c e i s i n v e r s e l y p r o p o r t i o n a l t o r^{2} s o t h e f o r c e b e c o m e f o r t h e s e p e r a t i o n 2 r = \frac{4.8}{4} = 1.2 N R e g a r d s$

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Q. Force between two identical short bar magnets whose centres are r metre apart is 4.8 N when their axes are in the same line. If the separation is increased to 2r metre, the force between them is reduced to 0.3 N 0.6 N 2.4 N 1.2 N

Dear Student, force is inversely proportional to r2so the force become for the seperation 2r=4.84=1.2 N Regards

Q. Force between two identical short bar magnets whose centres are r metre apart is 4.8 N when their axes are in the same line. If the separation is increased to 2r metre, the force between them is reduced to

0.3 N

0.6 N

2.4 N

1.2 N

Dear Student,

$f o r c e i s i n v e r s e l y p r o p o r t i o n a l t o r^{2} s o t h e f o r c e b e c o m e f o r t h e s e p e r a t i o n 2 r = \frac{4.8}{4} = 1.2 N R e g a r d s$