Brakes are applied to a truck to produce an acceleration of –10m/s2. If the truck takes 5s to stop after applying the brakes, the distance covered by the truck before coming to rest is 250m.
A
200 m
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B
125 m
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Solution
The correct option is B
125 m
Here, v=0 , a=−10m/s2 , t=5s Using v=u+at, 0=u+(−10×5) ⇒u=50m/s Also, v2 = u2+2as ⇒0=502+2×(−10)×s ⇒s=250020m ∴s=125m Therefore, the truck stops after 125m.