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BrO3- oxidise...

Question

${B r O_{3}}^{-}$ oxidises $I^{-}$ to $I_{2}$ and thus, equivalent weight of ${B r O_{3}}^{-}$ is $\frac{M}{x}$ . Here, $x$ is :

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Solution

$B r O_{3}^{-}$ oxidizes $I^{-}$ to $I_{2}$ .
In this reaction, $B r O_{3}^{-}$ is reduced to $B r^{-}$ .
The oxidation number of bromine changes from $+ 5$ to $- 1$ .
The net change in the oxidation number is $6$ .
Hence, equivalent weight of $B r O_{3}^{-}$ is $\frac{M}{6}$ .

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Similar questions

B r O_{3}^{-}

B r O_{4}^{-}

X e F_{2}

X e F_{2} m_{1} + B r O_{3}^{-} m_{2} + H_{2} O ⟶ B r O_{4}^{-} + X e + 2 H F

m_{1}

m_{2}

are the molar masses of

X e F_{2}

B r O_{3}^{-}

, respectively.

Ratio of equivalent mass of

X e F_{2}

B r O_{3}^{-}

A s O_{2}^{2 -} + B r O_{3}^{-} + H^{+} ⟶ B r^{-} + A s O_{4}^{-} + H_{2} O

Equivalent weight of

B r O_{3}^{-} = \frac{M}{x}

x

Q. In the reaction

B r O_{3}^{-} + 6 e^{-} + 6 H^{+} \to B r^{-} + 3 H_{2} O

, equivalent weight of

B r O_{3}^{-}

Q. Statement - 1 :

B r O_{3}^{-}

shows two reactions as

S e O_{3}^{-} + B r O_{3}^{-} + H^{+} \to S e O_{4}^{-} + B r_{2} + H_{2} O A s O_{2}^{-} + B r O_{3}^{-} + H^{+} \to B r^{-} + A s O_{4}^{-} + H_{2} O

and
Statement 2 - The ratio of equivalent weights of

B r O_{3}^{-}

in two reaction is

\frac{6}{5}

.

Q. In hot alkaline solution,

B r_{2}

disproportionates to

B r^{-}

{B r O_{3}}^{-}

.

3 B r_{2} + 6 O H^{-} \to 5 B r^{-} + {B r O_{3}}^{-} + 3 H_{2} O

Hence, equivalent weight of

B r_{2}

= M

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