Statement - 1 - BrO3- shows two reactions asSeO3- - BrO3- - H- - SeO4- - Br2 - H2OAsO2- - BrO3- - H- - Br- - AsO4- - H2Oand Statement 2 - The ratio of equivalent weights of BrO3- in two reaction is 65-

(i) SeO_3^ + +5BrO_3^ + H^+ → SeO_4^ + 0Br_2 + H_2O nbsp;E_BrO_3^ = M5 (ii) AsO_2^ + +5BrO_3^ + H^+ → 1Br^ + AsO_4^ + H_2O nbsp;E_BrO_3^ = M6 ∴ Ra ...

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Byju's Answer

Standard XII

Chemistry

Balancing Redox Equations

Statement - 1...

Question

Statement - 1 : $B r O_{3}^{-}$ shows two reactions as
$S e O_{3}^{-} + B r O_{3}^{-} + H^{+} \to S e O_{4}^{-} + B r_{2} + H_{2} O A s O_{2}^{-} + B r O_{3}^{-} + H^{+} \to B r^{-} + A s O_{4}^{-} + H_{2} O$
and
Statement 2 - The ratio of equivalent weights of $B r O_{3}^{-}$ in two reaction is $\frac{6}{5}$ .

Statement - 1 is True, Statement - 2 is true
Statement - 2 is a correct explanation for statement - 1

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Statement - 1 is true, statement 2 is true
Statement - 2 is not a correct explanation for statement 1

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Statement 1 is true, statement 2 is false

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Statement - 1 is false, statement - 2 is true

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Solution

The correct option is B Statement - 1 is true, statement 2 is true
Statement - 2 is not a correct explanation for statement 1
$(i) S e O_{3}^{-} + + 5 B r O_{3}^{-} + H^{+} \to S e O_{4}^{-} + 0 B r_{2} + H_{2} O E_{B r O_{3}^{-}} = \frac{M}{5} (i i) A s O_{2}^{-} + + 5 B r O_{3}^{-} + H^{+} \to - 1 B r^{-} + A s O_{4}^{-} + H_{2} O$
$E_{B r O_{3}^{-}} = \frac{M}{6}$

$∴$ Ratio $= \frac{6}{5}$

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Similar questions

Q. Assertion :

B r O_{3}^{-}

shows two reactions :

S e O_{3}^{2 -} + B r O_{3}^{-} + H^{+} ⟶ S e O_{4}^{2 -} + B r_{2} + H_{2} O

A s O_{2}^{2 -} + B r O_{3}^{-} + H^{+} ⟶ B r^{-} + A s O_{4}^{-} + H_{2} O

Reason: The ratio of equivalent masses of

B r O_{3}^{-}

in two reactions is

\frac{5}{6}

A s O_{2}^{2 -} + B r O_{3}^{-} + H^{+} ⟶ B r^{-} + A s O_{4}^{-} + H_{2} O

Equivalent weight of

B r O_{3}^{-} = \frac{M}{x}

. The value of

x

is :

Q. For the reactions,

B r_{2} + O H^{-} \to B r^{-} + B r O_{3}^{-} + H_{2} O

what is the equivalent weight of

B r_{2}

Q. In the reaction

B r O_{3}^{-} + 6 e^{-} + 6 H^{+} \to B r^{-} + 3 H_{2} O

, equivalent weight of

B r O_{3}^{-}

is:

Q. For the reaction,

B r O_{3}^{-} (a q) + 5 B r^{-} (a q) + 6 H^{+} \to 3 B r_{2} (l) + 3 H_{2} O (l)

, the rate equation can be expressed in two ways

\frac{d [B r_{2}]}{d t} = k [B r^{-}] [B r O_{3}] [H^{+}]^{2}

and

- \frac{d [B r^{-}]}{d t} = k^{'} [B r^{-}] [B r O_{3}] [H^{+}]^{2}

Here, k and k' are related as

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Statement - 1 : BrO−3 shows two reactions as SeO−3+BrO−3+H+→SeO−4+Br2+H2OAsO−2+BrO−3+H+→Br−+AsO−4+H2O and Statement 2 - The ratio of equivalent weights of BrO−3 in two reaction is 65.

The correct option is B Statement - 1 is true, statement 2 is true Statement - 2 is not a correct explanation for statement 1(i) SeO−3++5BrO−3+H+→SeO−4+0Br2+H2OEBrO−3=M5(ii) AsO−2++5BrO−3+H+→−1Br−+AsO−4+H2O EBrO−3=M6 ∴ Ratio =65