Balancing Redox Equations
Trending Questions
Q.
How many moles of K2Cr2O7 can be reduced by 1 mole of Sn+2
1
1/3
1/6
2/3
Q. C2H6(g)+nO2→CO2(g)+H2O(I)
In this equation, the ratio of the coefficients of CO2 and H2O is
In this equation, the ratio of the coefficients of CO2 and H2O is
- 2 : 3
- 1 : 1
- 3 : 2
- 1 : 3
Q.
The number of electrons involved in the reduction of Cr2O2−7 in acidic solution to Cr3+ is
5
0
2
3
Q. For the redox reaction xP4+yHNO3→H3PO4+NO2+H2O
- x = 2, y = 10
- x = 1, y = 15
- x = 1, y = 5
- x = 1, y = 20
Q. Oxidation of thiosulphate (S2O2−3) ion by iodine gives
- SO2−3
- SO2−4
- S4O2−6
- S2O2−6
Q.
When KMnO4 acts as an oxidizing agent and ultimately formsMnO−24 , MnO2 , Mn2O3 andMn+2 , then the number of electrons transferred ( per Mn atom) in each case respectively is:
4, 3, 1, 5
1, 5, 3, 7
1, 3, 4, 5
3, 5, 7, 1
Q. For decolourization of 1 mole of KMnO4, the moles of H2O2 required is
- 52
- 12
- 32
- 72
Q.
In the reaction, 8Al + 3Fe3O4→4Al2O3 + 9Fe, the number of electrons transferred from reductant to oxidant is:
4
7
24
8
Q. In a balanced equation
H2SO4+xHI→H2S+yI2+zH2O, the values of x, y, z are
H2SO4+xHI→H2S+yI2+zH2O, the values of x, y, z are
- x = 3, y = 5, z = 2
- x = 4, y = 8, z = 5
- x = 8, y = 4, z = 4
- x = 5, y = 3, z = 4
Q.
For the redox reaction
MnO−4+C2O−24+H+⟶Mn2++CO2+H2O
the correct coefficients of the reactants MnO−4, C2O2−4 and H+ for the balanced reaction are
2, 16, 5
2, 5, 16
16, 5, 2
5, 16, 2