For the reaction, BrO−3(aq)+5Br−(aq)+6H+→3Br2(l)+3H2O(l), the rate equation can be expressed in two ways d[Br2]dt=k[Br−][BrO3][H+]2 and −d[Br−]dt=k′[Br−][BrO3][H+]2
Here, k and k' are related as
A
3k′=k
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B
5k′=3k
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C
k′=5k
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D
3k′=5k
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Solution
The correct option is D3k′=5k For a reaction: aA→bB a,b are stoichiometric coefficients of reactant A and product B respectively Rate=−1a×d[A]dt=+1b×d[B]dt
So, for the reaction: BrO−3(aq)+5Br−(aq)+6H+→3Br2(l)+3H2O(l)
Writing rate in terms of Br− and Br2 Rate=−15×d[Br−]dt=+13×d[Br2]dt
⇒d[Br2]dt=−35d[Br−]dt.....eqn1
Given: d[Br2]dt=k[Br−][BrO3][H+]2......eqn(2) −d[Br−]dt=k′[Br−][BrO3][H+]2.......eqn(3)
Substituting equation (1) in (3), we get, 53d[Br2]dt=k′[Br−][BrO3][H+]2 d[Br2]dt=35k′[Br−][BrO3][H+]2.....eqn(4)