For the chemical reaction 5Br- - BrO3- - 6H- - 3Br2 - 3H2O Rate - k-Br-BrO3-H-2 The molecularity and order of reaction with respect to -Br- is-

The correct option is A 5, 1 As given, 5Br^⊖ + BrO_3^⊖ + 6H^⊕ → 3Br_2 + 3H_2O #160;5 #160; #160; #160; #160; #160;1 #160; ...

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Order of Reaction

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Question

For the chemical reaction $5 B r^{⊖} + B r O_{3}^{⊖} + 6 H^{\oplus} \to 3 B r_{2} + 3 H_{2} O$
Rate = $k [B r^{⊖}] [B r O_{3}^{⊖}] [H^{\oplus}]^{2}$ The molecularity and order of reaction with respect to $[B r^{⊖}]$ is:

5, 1

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1, 5

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1, 1

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6, 2

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For the chemical reaction $5 B r^{⊖} + B r O_{3}^{⊖} + 6 H^{\oplus} \to 3 B r_{2} + 3 H_{2} O$

Rate = $k [B r^{⊖}] [B r O_{3}^{⊖}] [H^{\oplus}]^{2}$ The order of reaction with respect to $[B r^{⊖}]$ is:

5 B r^{-} + B r O_{3}^{-} + 6 H^{+} \to 3 B r_{2} + 3 H_{2} O

B r_{2}

M

B r O_{3}^{-} (a q) + 5 B r^{-} (a q) + 6 H^{+} \to 3 B r_{2} (l) + 3 H_{2} O (l)

\frac{d [B r_{2}]}{d t} = k [B r^{-}] [B r O_{3}] [H^{+}]^{2}

- \frac{d [B r^{-}]}{d t} = k^{'} [B r^{-}] [B r O_{3}] [H^{+}]^{2}

B r O_{3}^{-} + 6 e^{-} + 6 H^{+} \to B r^{-} + 3 H_{2} O

B r O_{3}^{-}

3 {B r}_{2} + 6 C O_{3}^{2 -} + 3 H_{2} O ⟶ 5 {B r}^{⊖} + B r O_{3}^{⊖} + 6 H C O_{3}^{⊖}

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