Bromine gas ( ${Br}_{2}$ ) reacts with sodium carbonate ( ${Na}_{2} {CO}_{3}$ ) in aqueous solution and gives sodium bromide ( $NaBr$ ), sodium bromate ( ${NaBrO}_{3}$ ) and carbon-dioxide gas. How many sodium bromide molecules are obtained in the balanced chemical equation ? [2 MARKS]

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Solution

Each point: 1 Mark

1. From the question, we infer the unbalanced chemical equation is:
${Br}_{2} + {Na}_{2} {CO}_{3} \to NaBr + {NaBrO}_{3} + {CO}_{2}$
2. Balanced equation is:
$3 {Br}_{2} + 3 {Na}_{2} {CO}_{3} \to 5 NaBr + {NaBrO}_{3} + 3 {CO}_{2}$
It means 5 molecules of NaBr are obtained.

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Q. Reaction of

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Bromine gas (Br2) reacts with sodium carbonate (Na2CO3) in aqueous solution and gives sodium bromide (NaBr), sodium bromate (NaBrO3) and carbon-dioxide gas. How many sodium bromide molecules are obtained in the balanced chemical equation ? [2 MARKS]

Each point: 1 Mark 1. From the question, we infer the unbalanced chemical equation is: Br2+Na2CO3→NaBr+NaBrO3+CO2 2. Balanced equation is: 3Br2+3Na2CO3→5NaBr+NaBrO3+3CO2 It means 5 molecules of NaBr are obtained.

Bromine gas ( ${Br}_{2}$ ) reacts with sodium carbonate ( ${Na}_{2} {CO}_{3}$ ) in aqueous solution and gives sodium bromide ( $NaBr$ ), sodium bromate ( ${NaBrO}_{3}$ ) and carbon-dioxide gas. How many sodium bromide molecules are obtained in the balanced chemical equation ? [2 MARKS]

Each point: 1 Mark

1. From the question, we infer the unbalanced chemical equation is:
${Br}_{2} + {Na}_{2} {CO}_{3} \to NaBr + {NaBrO}_{3} + {CO}_{2}$
2. Balanced equation is:
$3 {Br}_{2} + 3 {Na}_{2} {CO}_{3} \to 5 NaBr + {NaBrO}_{3} + 3 {CO}_{2}$
It means 5 molecules of NaBr are obtained.