$B u n a - N$ , a synthetic rubber is copolymer of:

H_{2} C = C H - C H = C H_{2}

and

H_{5} C_{6} - C H = C H_{2}

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H_{2} C = C H - C N

and

H_{2} C = C H - C H = C H_{2}

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H_{2} C = C H - C l | C = C H_{2}

and

H_{2} C = C H - C H = C H_{2}

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H_{2} C = C N - C N

and

H_{2} C = C H - C | C l = C H_{2}

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Solution

The correct option is A $H_{2} C = C H - C N$ and $H_{2} C = C H - C H = C H_{2}$
$B u n a - N$ , a synthetic rubber is copolymer of acrylonitrile, $H_{2} C = C H - C N$ and $1, 3 - b u t a d i e n e$ , $H_{2} C = C H - C H = C H_{2}$
It is used in making soles of the shoes, adhesives, tank lining, oil seals etc.

$n H_{2} C = C H - C N + n H_{2} C = C H - C H = C H_{2} \to - [C H_{2} - C H = C H - C H_{2} - C H_{2} C H (C N)] - Buna-N$
Hence, option B is correct.

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Similar questions

C H \equiv C H

C H_{2} = C H_{2}

H_{2} C = C H - C l

H C | C l = C H | C l

H_{2} C = C H - C H = C H_{2}

H_{2} C = C H - C H | O H - {C H}_{2} - {C H}_{2} - {C H}_{3}

H_{2} C = C H - C H_{2} - C H_{2} - C H_{3}

H_{2} C = C H - C H = C H_{2} B r_{2} (1 mole) - ------ \to 60^{o} C (A) i . K C N (excess) - -------- \to i i . H_{2} / N i

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