By grouping the terms in a3-7 a2-b a-7 b-a-7- we get

The correct option is C (a + 7) (a2 + b 1)a3 + 7a2 + ba + 7b a 7 = a2 (a + 7) + b (a + 7) 1 (a + 7) = (a + 7) (a2 + b 1) ...

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Sequence

By grouping t...

Question

By grouping the terms in a³ + 7a² + ba + 7b - a - 7, we get

(a - 7) (a² + b² - 1)

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(a + 7) (a² + b + 1)

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(a + 7) (a² + b - 1)

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(a + 7) (a² - b + 1)

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6 a^{3} + 5 a - 2 a^{2} - 7

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a_{1}, a_{2}, a_{3} \dots

I f \frac{a_{1} + a_{2} + \dots a_{p}}{a_{1} + a_{2} + \dots + a_{q}} = \frac{p^{2}}{q^{2}}, p \neq q,

\frac{a_{6}}{a_{21}}

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