By inserting a capillary tube upto a depth l in water, the water rises to a height h. If the lower end of the capillary is closed inside water and the capillary is taken out and closed end opened, to what height the water will remain in the tube

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Solution

The correct option is C
h
As we know, $h = \frac{(2 T c o s θ)}{σ g r}; σ = d e n s i t y o f t h e l i q u i d$

The water rises to height h due to capillarity.

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By inserting a capillary tube upto a depth l in water, the water rises to a height h. If the lower end of the capillary is closed inside water and the capillary is taken out and closed end opened, to what height the water will remain in the tube

The correct option is ChAs we know, h=(2Tcosθ)σgr;σ=densityoftheliquid The water rises to height h due to capillarity.

The correct option is C
h
As we know, $h = \frac{(2 T c o s θ)}{σ g r}; σ = d e n s i t y o f t h e l i q u i d$

The water rises to height h due to capillarity.