By selling oranges at the rate of Rs 334 per orange- a man gets Rs 210 - How many oranges does he sell-

Cost of 1 orange = Rs 334 = Rs 154 Total cost of the oranges sold by the man = Rs 210 there4; Required number of oranges = 210 #247;154 nbsp; nbsp; ...

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Standard VII

Mathematics

Complementary Events

By selling or...

Question

By selling oranges at the rate of Rs $3 \frac{3}{4}$ per orange, a man gets Rs 210. How many oranges does he sell?

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Solution

Cost of 1 orange = Rs $3 \frac{3}{4}$ = Rs $\frac{15}{4}$
Total cost of the oranges sold by the man = Rs 210

∴ Required number of oranges = $(210 \div \frac{15}{4})$
= $(210 \times \frac{4}{15})$ [∵ Reciprocal of $\frac{15}{4}$ = $\frac{4}{15}$ ]
= (14 $\times$ 4) = 56

Hence, the man sold 56 oranges.

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By selling oranges at the rate of Rs 334 per orange, a man gets Rs 210. How many oranges does he sell?

Cost of 1 orange = Rs 334 = Rs 154 Total cost of the oranges sold by the man = Rs 210 ∴ Required number of oranges = 210÷154 = 210×415 [∵ Reciprocal of 154 = 415] = (14 × 4) = 56 Hence, the man sold 56 oranges.

By selling oranges at the rate of Rs $3 \frac{3}{4}$ per orange, a man gets Rs 210. How many oranges does he sell?