By simplifying 4rr2m2- we get -

The correct option is C 4/r^3 m^2 4r(r^2m)^2 #160; 4rr^4m^2=4r^3m^2 ...

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Units and Dimensions

By simplifyin...

Question

By simplifying $\frac{4 r}{(r^{2} m)^{2}}$ , we get :

1 / 2 m

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4 / r^{3} m

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4 r / r^{5} m

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4 / r^{3} m^{2}

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Solution

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Similar questions

(3 k - 4 r - 2 m)^{2} - (3 k + 4 r - 2 m)^{2}

Simplify:
$(3 k - 4 r - 2 m)^{2} + (3 k + 4 r - 2 m)^{2}$

(2 p + 3 q - 4 r)^{2} + (2 p - 3 q - 4 r)^{2}

^{34} C_{5} + 4 \sum r = 0^{(38 - r)} C_{4}

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