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Ideal Gas Equation

By the ideal ...

Question

By the ideal gas law, the pressure of $0.60$ moles ${N H}_{3}$ gas in a $3.00 L$ vessel at $25^{o} C$ is, given that $R = 0.082 L$ atm ${m o l}^{- 1} k^{- 1}$ :

48.9 a t m

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4.89 a t m

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0.489 a t m

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489 a t m

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Solution

The correct option is A $4.89 a t m$
Pressure is given as $P = \frac{n R T}{V} = \frac{0.6 \times .082 \times (25 + 273)}{3} = 4.89 a t m$
Option B is correct.

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