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Question

By using properties of definite integrals, evaluate the integrals
10x(1x)ndx.

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Solution

Let 10x(1x)ndx.
I=10(1x){(1x)1(1x)}ndx[a0f(x)dx=a0f(ax)dx]
=10(1x)xndx==10(xnxn+1)dx
=[xn+1n+1xn+2n+2]10=[1n+11n+2]=0
=(n+2)(n+1)(n+1)(n+2)=1(n+1)(n+2)


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