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Question

By using properties of definite integrals, evaluate the integrals
2π0cos5xdx.

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Solution

2π0cos5xdx=2π0cos5xdx(2a0f(x)=2a0f(x)dx, where f(2ax)=f(x);hence,2a=2xcos5(2xx)=cos5x)=2×0=0(2a0f(x)=0,if f(2ax)=f(x);here2a=πcos5(πx)=cos5x)


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