wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

By using properties of definite integrals, evaluate the integrals
2π0cos5xdx.

Open in App
Solution

2π0cos5xdx=2π0cos5xdx(2a0f(x)=2a0f(x)dx, where f(2ax)=f(x);hence,2a=2xcos5(2xx)=cos5x)=2×0=0(2a0f(x)=0,if f(2ax)=f(x);here2a=πcos5(πx)=cos5x)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon