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Question

By using properties of definite integrals, evaluate the integrals
π20sinxsinx+cosxdx

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Solution

Let I= π20sinxsinx+cosxdx

Then I=π20sin(π2)xsin(π2x)+cos(π2x)dxI=π20cosxcosx+sinxdx[sin(π2x)=cos x and cos(π2x)=sin x]
On adding Eqs. (i) and (ii) , we get 2I=π20sinx+cosxsinx+cosxdx=π201dx=[x]π20=π201=π4


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