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Question

By using properties of definite integrals, evaluate the integrals
π2π2sin7xdx.

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Solution

π2π2sin7xdx.
Here, f(x)=sin7xf(x)=sin7(x)=[sinx]7=sin7xf(x)=f(x)So, f(x) is an odd function.π2π2sin7xdx.=0[aaf(x)dx=0 if f(x) is an odd function


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