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Question

By walking at 34th of his usual speed, a man reaches office 20 minutes later than usual. What is his usual time?

A
30 minutes
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B
60 minutes
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C
70 minutes
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D
50 minutes
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Solution

The correct option is B 60 minutes
Let:
Distance covered be d
Usual speed be s
Usual time (in minutes) be t

Distance is the product of speed and time.
d=st(i)

When the person walks with 34th of his usual speed,
Speed is: s2=34s
Time is: t2=t+20
Again, applying distance formula:
d=s2t2
d=34s(t+20)(ii)

Equating equations (i) and (ii),
34s(t+20))=st
3t+60=4t
t=60 minutes

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