By weight, $90 %$ of tomato and $78 %$ of potato is water. Find the total quantity, by weight, of water in $90 k g$ of potato and $30 k g$ of tomato.

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Solution

Step 1: Finding the weight of water in $90 k g$ of potato

Given:

Weight of water in a potato $= 78 %$ of the total weight of potato.

Therefore,

Weight of water in $90 k g$ of potato

$= 78 %$ of $90 k g$

$= 78 % \times 90$

$= \frac{78}{100} \times 90$

$= \frac{9 \times 78}{10} = \frac{702}{10} = 70.2 k g$

So, the weight of water in $90 k g$ of potato is $70.2 k g$ .

Step 2: Finding the weight of water in $30 k g$ of tomato

Given: Weight of water in a tomato $= 90 %$ of the total weight of tomato.

Therefore,

Weight of water in $30 k g$ of tomato

$= 90 %$ of $30 k g$

$= 90 % \times 30$

$= \frac{90}{100} \times 30$

$= \frac{9 \times 30}{10}$

$= 27 k g$

So, the weight of water in $30 k g$ of tomato is $27 k g$ .

Step 3: Finding the total weight of water in the given quantity

Given:

As, the weight of water in $90 k g$ of potato is $70.2 k g$ and the weight of water in $30 k g$ of tomato is $27 k g$ .

Therefore,

The total weight of water in the given quantity $=$ weight of water in $90 k g$ of potato $+$ weight of water in $30 k g$ of tomato

$= 70.2 + 27$

$= 97.2 k g$

Hence, the total quantity, by weight, of water in $90 k g$ of potato and $30 k g$ of tomato is $97.2 k g$ .

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