C 2 H 5 Cl A B Here A and B are -

The correct option is C C _ 2 H _ 4 , C _ 2 H _ 5 OH Reaction of the process: CH_3 CH_2Cl+KOHCH_2=CH_2+KCl+H_2O In this process alc. KOH is used fo ...

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Byju's Answer

Standard XII

Chemistry

Interhalogen Compounds - Chemical Properties

C 2 H 5 Cl A ...

Question

$C_{2} H_{5} C l A l c o h o l i c K O H - -------- \to A d i l . H_{2} {S O}_{4} / H_{2} O - --------- \to B$

Here A and B are :

C_{2} H_{5} O H, C_{2} H_{4}

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C_{2} H_{4}, C_{2} H_{5} O H

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C_{3} H_{8}, C_{2} H_{5} O H

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C_{2} H_{2}, C_{2} H_{5} O H

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Solution

The correct option is C $C_{2} H_{4}, C_{2} H_{5} O H$
Reaction of the process: $C H_{3} - C H_{2} C l + K O H A l c o h o l - --- \to C H_{2} = C H_{2} + K C l + H_{2} O$
In this process alc. KOH is used for dehydrohalogenation.

And then in presence of aq. $H_{2} S O_{4}$ ,
$C H_{2} = C H_{2} + H_{2} O \to C_{2} H_{5} O H$

Option B is correct.

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Similar questions

Q. Calculate the thermal effect of the reaction

C_{2} H_{4} + H_{2} O = C_{2} H_{5} O H

, if

{Δ H}_{f o r m}^{o} (C_{2} H_{4}) = 55, 28 K J / m o l

{Δ H}_{f o r m}^{o} (H_{2} O) = - 241.8 K J / m o l

{Δ H}_{f o r m}^{o} (C_{2} H_{5} O H) = - 235.3 K J / m o l

C_{2} H_{5} O H

ionises as:

C_{2} H_{5} O H

can be differentiated from

{C H}_{3} O H

by:

Q. Acetaldoxime on reduction with

N a / C_{2} H_{5} O H

gives:

Arrange the following in the increasing order of their boiling point:

C_{2} H_{5} O H, {(C H}_{3})_{2} N H, C_{2} H_{5} {N H}_{2}

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C2H5ClAlcoholicKOH−−−−−−−−−→Adil.H2SO4/H2O−−−−−−−−−−→B Here A and B are :

The correct option is C C2H4,C2H5OHReaction of the process: CH3−CH2Cl+KOHAlcohol−−−−→CH2=CH2+KCl+H2OIn this process alc. KOH is used for dehydrohalogenation.And then in presence of aq. H2SO4,CH2=CH2+H2O→C2H5OHOption B is correct.

$C_{2} H_{5} C l A l c o h o l i c K O H - -------- \to A d i l . H_{2} {S O}_{4} / H_{2} O - --------- \to B$

Here A and B are :