C2H61000oC−−−−→Δ A S2Cl2−−−→ B. Here B is :
A
(C2H5)2S
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B
(C2H4Cl)2S
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C
(CH3Cl)2S
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D
(CH3)3S
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Solution
The correct option is B(C2H4Cl)2S In ethane combustion, the combination of an ethyl radical with oxygen takes place, and the subsequent breakup of the resulting peroxide into ethoxy and hydroxyl radicals.In the range 6000Cto9000C, ethylene is formed. Ethylene, on combining with S2Cl2, forms mustard gas CH2=CH2+S2Cl2→(C2H4Cl)2S