$C_{2} H_{6} (g) + n O_{2} \to C O_{2} (g) + H_{2} O (I)$
In this equation, the ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is

1 : 1

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2 : 3

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3 : 2

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1 : 3

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Solution

The correct option is B 2 : 3
The balanced equation is $2 C_{2} H_{6} + 7 O_{2} \to 4 C O_{2} + 6 H_{2} O$ . Ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is 4 : 6 or 2 : 3.

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C_{2} H_{6} (g) + n O_{2} \to C O_{2} (g) + H_{2} O (I)

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For the reaction $C_{2} H_{6} (g) + n O_{2} ⟶ C O_{2} (g) + H_{2} O (l)$ , the ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is:

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