C 6 H 5 COOH 2- - 1- N H 3 P NaOBr Q 2- heat to 460K 1- Conc- H 2 S O 4 -R- R- is -

The correct option is D sulphanilic acid C_6H_5COOHPC_6H_5CONH_2QC_6H_5NH_2Rp sulphanilic acid R is H_2N C_6H_4 SO_3H Option D is correct ...

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Reduction of Carboxylic Acids

C 6 H 5 COOH ...

Question

$C_{6} H_{5} C O O H 1. N H_{3} - ------ \to 2. Δ P N a O B r - ----- \to Q 1. C o n c . H_{2} S O_{4} - -------------- \to 2. h e a t t o 460 K^{'} R^{'}$
' $R$ ' is :

sulphanilamide

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p

-bromo sulphanilamide

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o

-bromo sulphanilic acid

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sulphanilic acid

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Solution

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Arrange the compounds of each set in order of reactivity towards S_N2 displacement:

(i) 2-Bromo-2-methylbutane, 1-Bromopentane, 2-Bromopentane

(ii) 1-Bromo-3-methylbutane, 2-Bromo-2-methylbutane, 3-Bromo-2- methylbutane

(iii) 1-Bromobutane, 1-Bromo-2,2-dimethylpropane, 1-Bromo-2-methylbutane, 1-Bromo-3-methylbutane.

(C H_{3})_{2} C H - C H_{2} - C H_{2} B r

Which is the correct IUPAC name for

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