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Halogenation of Benzene

C 6 H 6 +A+Al...

Question

$C_{6} H_{6} + A + A l {C l}_{3} ⟶ C_{6} H_{5} C O {N H}_{2}$ ;
Here A is:

urea

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C l C O {N H}_{2}

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{C H}_{3} C O {N H}_{2}

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C l {C H}_{2} C O {N H}_{2}

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Solution

The correct option is B $C l C O {N H}_{2}$
This is friedel craft acylation reaction
$C_{6} H_{6} + N H_{2} C O C l + A l {C l}_{3} ⟶ C_{6} H_{5} C O {N H}_{2}$
So A is $N H_{2} C O C l$

Suggest Corrections

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