Question

$C_6{H}_{5}N{H}_2+CHC{l}_3\underset{\Delta }{\overset{AlC.KOH}{\to }}\times \stackrel{H_3{O}^{-}}{\to }Y$

Y is :

Answer 1

$C_6{H}_{5}N{H}_2+CHC{l}_3\underset{\Delta }{\overset{Alc.KOH}{\to }}{C}_6{H}_5{N}^{+}\equiv C^{-}\stackrel{H_3{O}^{+}}{\to }{C}_6{H}_{5}N{H}_2+HCOOH$

In the first step, the aniline ($C_6{H}_{5}N{H}_2$) undergoes carbylamine reaction to form foul-smelling phenyl isocyanide.

This product when reacts with $H_3{O}^{+}$ forms aniline along with formic acid as a product.

Y is Formic acid or $HCOOH$