Question

Catherine threw a dice $40$ times and noted the number appearing each time as shown below:

Make a table and enter the data using tally marks. Find those numbers that appear an equal number of times.

$\begin{array}{cccccccccc}1& 3& 5& 6& 6& 3& 5& 4& 1& 6\\ 2& 5& 3& 4& 6& 1& 5& 5& 6& 1\\ 1& 2& 2& 3& 5& 2& 4& 5& 5& 6\\ 5& 1& 6& 2& 3& 5& 2& 4& 1& 5\end{array}$

Answer 1

The number $1$ is represented as |. The number $2$ is represented as || and so on. But number $5$ is represented as ​​​​$||||$

$\begin{array}{ccc}\text{Number}& \text{Tally Marks}& \text{Frequency (How many times?)}\\ 1& ||||||& 7\\ 2& |||||& 6\\ 3& ||||& 5\\ 4& ||||& 4\\ 5& |||||||||& 11\\ 6& ||||||& 7\end{array}$

The number $"1"$ and the number $"6"$ both appeared an equal number of times, i.e, $7$ times.