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Byju's Answer
Standard XII
Chemistry
Hess' Law
Cs + O2g → CO...
Question
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
,
Δ
H
=
+
94.0
K
c
a
l
.
C
O
(
g
)
+
1
2
O
2
(
g
)
→
C
O
2
(
g
)
,
Δ
H
=
−
67.7
K
c
a
l
.
From the above reactions find how much heat (Kcal mole
−
1
) would be produced in the following reaction:
C
(
s
)
+
1
2
O
2
(
g
)
→
C
O
(
g
)
A
20.6
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B
26.3
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C
44.2
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D
161.7
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Solution
The correct option is
D
161.7
The thermochemical reactions are as given below.
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
Δ
H
=
+
94.0
K
c
a
l
.
......(1)
C
O
(
g
)
+
1
2
O
2
(
g
)
→
C
O
2
(
g
)
,
Δ
H
=
−
67.7
K
c
a
l
......(2)
The reaction (2) is reversed and added to the reaction (1) to obtain the reaction
C
(
s
)
+
1
2
O
2
(
g
)
→
C
O
(
g
)
.
The heat produced in this reaction is
94.0
−
(
−
67.7
)
=
161.7
Kcal/mole
Suggest Corrections
0
Similar questions
Q.
C
(
s
)
+
O
2
(
g
)
→
C
O
2
,
(
g
)
;
Δ
H
=
−
94.3
kcal/mol
C
O
(
g
)
+
1
2
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
67.4
kcal/mol
O
2
(
g
)
→
2
O
(
g
)
;
Δ
H
=
117.4
kcal/mol
C
O
(
g
)
→
C
(
g
)
+
O
(
g
)
;
Δ
H
=
230.6
kcal/mol.
Calculate
Δ
H
for
C
(
s
)
→
C
(
g
)
in kcal/mol.
Q.
Consider the following reaction
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
+
x
k
J
C
O
(
g
)
+
1
2
O
2
(
g
)
⟶
C
O
2
(
g
)
+
y
k
J
The heat of formation of
C
O
(
g
)
is:
Q.
Calculate
Δ
H
in
k
J
for the following reaction:
C
(
g
)
+
O
2
(
g
)
→
C
O
2
(
g
)
Given that,
H
2
O
(
g
)
+
C
(
g
)
→
C
O
(
g
)
+
H
2
(
g
)
;
Δ
H
=
+
131
k
J
C
O
(
g
)
+
1
2
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
282
k
J
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
g
)
;
Δ
H
=
−
242
k
J
Q.
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
94.3
kcal/mol
C
O
(
g
)
+
1
/
2
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
67.4
kcal/mol
O
2
(
g
)
→
2
O
(
g
)
;
Δ
H
=
117.4
kcal/mol
C
O
(
g
)
→
C
(
g
)
+
O
(
g
)
;
Δ
H
=
230.6
kcal/mol
Calculate
Δ
H
for
C
(
s
)
→
C
(
g
)
in Kcal/mol.
Q.
Which of the following equations has have enthalpy changes equal to
Δ
H
c
o
m
b
C
I
.
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
I
I
.
C
(
s
)
+
1
2
O
2
(
g
)
⟶
C
O
(
g
)
I
I
I
.
C
O
(
g
)
+
1
2
O
2
(
g
)
⟶
C
O
2
(
g
)
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