Cs - O2g - CO2g- - H - - 94-3 kcal-mol COg - 1-2 O2g - CO2g- - H - - 67-4 kcal-mol O2g - 2Og- - H - 117-4 kcal-mol COg - Cg - Og- - H - 230-6 kcal-molCalculate - H for C s - Cg in Kcal-mol-

The correct option is D 145 C(s) + O_2(g) → CO_2(g); Δ H = 94.3 kcal/mol ......(1) CO(g) + 1/2 O_2(g) → CO_2(g); Δ H = 67.4 kcal/mol ...

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Introduction

Cs + O2g → CO...

Question

$C (s) + O_{2} (g) \to C O_{2} (g); Δ H = - 94.3$ kcal/mol
$C O (g) + 1 / 2 O_{2} (g) \to C O_{2} (g); Δ H = - 67.4$ kcal/mol
$O_{2} (g) \to 2 O (g); Δ H = 117.4$ kcal/mol
$C O (g) \to C (g) + O (g); Δ H = 230.6$ kcal/mol
Calculate $Δ H$ for $C (s)$ $\to$ $C (g)$ in Kcal/mol.

171

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Solution

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Similar questions

C (s) + O_{2} (g) \to C O_{2}, (g);

Δ H = - 94.3

C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g);

Δ H = - 67.4

O_{2} (g) \to 2 O (g);

Δ H = 117.4

C O (g) \to C (g) + O (g);

Δ H = 230.6

Δ H

C (s) \to C (g)

C (s) + O_{2} (g) \to C O_{2}, (g); △ H = - 94.3 k c a l / m o l

C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g); △ H = - 67.4 k c a l / m o l

O_{2} (g) \to 2 O (g); △ H = 117.4 k c a l / m o l

C O (g) \to C (g) + O (g); △ H = 230.6 k c a l / m o l

△ H

C (s) \to C (g)

k c a l / m o l

$C (s) + O_{2} (g) \to C O_{2} (g), Δ_{r} H = - 94.3 k c a l / m o l$

$C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g), Δ_{r} H = - 67.4 k c a l / m o l$

$O_{2} (g) \to 2 O (g), Δ_{r} H = 117.4 K c a l / m o l$

$C O (g) \to C (g) + O (g), Δ_{r} H = 230.6 K c a l / m o l$

Calculate: $Δ_{r} H f o r C (s) \to C (g) i n K c a l / m o l$

C (s) + O_{2} (g) \to C O_{2} (g), Δ H = + 94.0 K c a l .

C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g), Δ H = - 67.7 K c a l .

^{- 1}

C (s) + \frac{1}{2} O_{2} (g) \to C O (g)

C (s) + O_{2} (g) \to C O_{2} (g), Δ H = - 94

2 C O (g) + O_{2} \to 2 C O_{2} (g), Δ H = - 135.2

C O (g)

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