Question 58 (c)
Subtract:
−4x2y−y3 from x3+3xy2−x2y.
We have, x3+3xy2−x2y−(−4x2y−y3)=x3+3xy2−x2y+4x2y+y3=x3+y3+3x2y+3xy2
Question 57 (b)
Add the following expression:
x3−x2y−xy2−y3 and x3−2x2y+3xy2+4y
Question 60 (a)
What should be subtracted from 2x3−3x2y+2xy2+3y3 to get x3−2x2y+3xy2+4y3?
Question 59 (a)
What should be added to x3+3x2y+3xy2+y3 to get x3+y3?