Calcium carbonate decomposes on heating according to the equation:

$C a C O_{3}$ (s) $⟶$ CaO(s)+ $C O_{2}$

At STP, the volume of $C O_{2}$ obtained by thermal decomposition of 50g of $C a C O_{3}$ will be:

22.4 litre

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44 litre

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11.2 litre

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1 litre

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Solution

The correct option is C
11.2 litre

$C a C O_{3}$ (s) $⟶$ CaO(s)+ $C O_{2}$

50gm $\frac{1}{2}$ mole =11.2lit

= $\frac{1}{2}$ mole

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