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Question

What will be the volume of CO2 at NTP obtained on heating 10 grams of (90% pure) limestone


A
22.4 litre
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B
2.016 litre
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C
2.24 litre
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D
20.16 litre
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Solution

The correct option is B 2.016 litre
CaCO3CaO+CO2
10 gm
90% pure 9gm =9100 mole
CaCO3CO2=0.09 mole
At NTP Vol.CO2=0.09×22.4=2.016 L

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