What will be the volume of CO 2 at NTP obtained on heating 10 grams of 90- pure limestone-A- 22-4 litresB- 2-24 litresC- 2-016 litresD- 20-16 litres

The correct option is C 2.016 litresThe given decomposition reaction is, CaCO_3→ CaO+CO_2 Mass of CaCO_3 taken is = 10/100×90=9 g Again, 9 g CaCO_3=9/1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Stoichiometric Calculations

What will be ...

Question

What will be the volume of $C O_{2}$ at NTP obtained on heating 10 grams of (90% pure) limestone?

22.4 l i t r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20.16 l i t r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.24 l i t r e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.016 l i t r e s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2.016 l i t r e s$
The given decomposition reaction is,
$C a C O_{3} \to C a O + C O_{2}$

$M a s s o f C a C O_{3} t a k e n i s = \frac{10}{100} \times 90 = 9 g$

Again, $9 g C a C O_{3} = \frac{9}{100} m o l C a C O_{3} = 0.09 m o l C a C O_{3}$

$S o C O_{2} p r o d u c e d = 0.09 \times 22.4 L = 2.016 L$

Suggest Corrections

Similar questions

What will be the volume of $C O_{2}$ at NTP obtained on heating 10 grams of ( $90 %$ pure) limestone

Q. What volume of

C O_{2}

(measured at STP) is obtained on heating 10 grams of 90% pure limestone?

Q. What will be the volume of

C O_{2}

at STP (atm) obtained on heating 10 grams of 90% pure limestone?

Volume of 4.4g of $C O_{2}$ at STP is

Q. What will be the volume of

C O_{2}

at NTP obtained on heating 10 grams of (90% pure) limestone?

Join BYJU'S Learning Program

What will be the volume of CO2 at NTP obtained on heating 10 grams of (90% pure) limestone?

The correct option is D 2.016 litresThe given decomposition reaction is, CaCO3→CaO+CO2 Mass of CaCO3 taken is=10100×90=9 g Again, 9 g CaCO3=9100 mol CaCO3=0.09 mol CaCO3 So CO2 produced=0.09×22.4 L=2.016 L

What will be the volume of $C O_{2}$ at NTP obtained on heating 10 grams of (90% pure) limestone?