wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Calcium carbonate reacts with aqueous HCI to give CaCl2 and CO2 according to the reactions:
CaCO3(s)+2HCl(aq)CaCl2(aq)+CO2(g)+H2OWhat mass of CaCO3 is required to completely react with 25 mL of 0.75 M HCl?

A
0.253 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.425 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.9375 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.9375 g
1000ml of 0.75 M HCl = 0.75 mol

So, 25 ml of HCl will contain HCl = 0.75×25/1000 = 0.01875
2 mol of HCl reacts with 1 mol of CaCO3

So, 0.01875 mol of HCl will react with 12 × 0.01875 = 0.009375 mol

Molar mass of CaCO3 = 100 g

Hence, the mass of 0.009375 mol of CaCO3 = no. of moles × molar mass
= 0.009375× 100
= 0.9375 g
Hence, the correct option is C.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Calcium Carbonate
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon