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Question

Calcium carbonate reacts with aqueous HCI to give CaCl2 and CO2 according to the reactions:
CaCO3(s)+2HCl(aq)CaCl2(aq)+CO2(g)+H2OWhat mass of CaCO3 is required to completely react with 25 mL of 0.75 M HCl?

A
0.253 g
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B
0.425 g
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C
0.9375 g
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D
None of these
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Solution

The correct option is C 0.9375 g
1000ml of 0.75 M HCl = 0.75 mol

So, 25 ml of HCl will contain HCl = 0.75×25/1000 = 0.01875
2 mol of HCl reacts with 1 mol of CaCO3

So, 0.01875 mol of HCl will react with 12 × 0.01875 = 0.009375 mol

Molar mass of CaCO3 = 100 g

Hence, the mass of 0.009375 mol of CaCO3 = no. of moles × molar mass
= 0.009375× 100
= 0.9375 g
Hence, the correct option is C.

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