Calcium carbonate reacts with aqueous HCl according to the reaction- CaCO3s-2HClaq- CaCl2aq-CO2g-H2OlWhat mass of CaCO3 is required to react completely with 25 ml of 0-75 M HCl-

1000 ml of 0.75 M Hd #160; have 0.75 mol of Hd=(0.75) (36.5)=24.375 g ∴ mass of Hd in 25 ml of 0.75 M Hd=24.3751 ...

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Standard XII

Chemistry

Uses of Calcium Carbonate

Calcium carbo...

Question

Calcium carbonate reacts with aqueous $H C l$ according to the reaction:
$C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$
What mass of $C a C O_{3}$ is required to react completely with $25$ ml of $0.75$ M $H C l$ ?

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Solution

$1000 m l$ of $0.75 M H d$ have $0.75$ mol of $H d = (0.75) (36.5) = 24.375 g$
$∴$ mass of $H d$ in $25 m l$ of $0.75 M H d = \frac{24.375}{1000} \times 25 g = 0.6844 g$
$\begin{matrix} {C a C O}_{3_{(5)}} & + & {2 H C l}_{(a q)} & ⟶ & {C a C l}_{2_{(a q)}} & + & {C O}_{2_{(g)}} & H_{2} O_{(l)} \end{matrix}$
$2$ moles of $H d$ i.e., $73 g H C l$ react completely with $1$ mole of $C a C O_{3}$ i.e., $100$ grams
$∴ 0.6844 H d$ reacts with $C a C O_{3} = (\frac{100}{73}) (0.6844) = 0.938 g$

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Similar questions

Calcium carbonate reacts with aqueous HCl to give CaCl₂ and CO₂ according to the reaction, CaCO₃₍_s₎ + 2 HCl₍_aq₎ → CaCl₂₍_aq₎ + CO₂₍_g) + H₂O₍_l₎

What mass of CaCO₃ is required to react completely with 25 mL of 0.75 M HCl?

Q. Calcium carbonate reacts with aqueous

H C l

to give

C a C l_{2} and C O_{2}

according to the raction,

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

.
The mass of

C a C O_{3}

is required to react compelety with

25

mL

0.75 M

HCI

is:

Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

Q. Calcium carbonate reacts with aqueous

H C I

to give

C a C l_{2}

and

{C O}_{2}

according to the reactions:

C a {C O}_{3 (s)} + 2 H C l_{(a q)} \to C a {C l}_{2 (a q)} + {C O}_{2 (g)} + H_{2} O

What mass of

C a C O_{3}

is required to completely react with

25 m L

0.75 M H C l

Q. Calcium carbonate (

10

g) reacts with aqueous

H C l

(

0.3

mol) according to the reaction,

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

The number of moles of

C a C l_{2}

formed in the reaction is:

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Calcium carbonate reacts with aqueous HCl according to the reaction:CaCO3(s)+2HCl(aq)→CaCl2(aq)+CO2(g)+H2O(l)What mass of CaCO3 is required to react completely with 25 ml of 0.75 M HCl?

Calcium carbonate reacts with aqueous $H C l$ according to the reaction:
$C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$
What mass of $C a C O_{3}$ is required to react completely with $25$ ml of $0.75$ M $H C l$ ?