Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the raction-CaCO3s-2HClaq- CaCl2aq-CO2g-H2Ol-The mass of CaCO3 is required to react compelety with 25 mL of 0-75 M HCI is-

CaCO_3+2HCl(aq)→ CaCl_2+CO_2+H_2O n= 25× 0.751000 Moles of CaCO_3 required= 25× 0.751000×12 Mass of CaCO_3= 25× 0.751000×12× 100= 0.9375 g ...

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Standard XII

Chemistry

Empirical & Molecular Formula

Calcium carbo...

Question

Calcium carbonate reacts with aqueous $H C l$ to give $C a C l_{2} and C O_{2}$ according to the raction, $C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$ .
The mass of $C a C O_{3}$ is required to react compelety with $25$ $mL$ of $0.75 M$ $HCI$ is:

0.1 g

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0.5 g

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1.5 g

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0.94 g

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Solution

The correct option is D $0.94 g$
$C a C O_{3} + 2 H C l (a q) \to C a C l_{2} + C O_{2} + H_{2} O$
$n = \frac{25 \times 0.75}{1000}$

Moles of $C a C O_{3} required = \frac{25 \times 0.75}{1000} \times \frac{1}{2}$
Mass of $C a C O_{3} = \frac{25 \times 0.75}{1000} \times \frac{1}{2} \times 100 = 0.9375 g$

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Similar questions

Q. Calcium carbonate reacts with aqueous HCl to give

C a C l_{2}

and

C O_{2}

according to the reaction -

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

The mass of

C a C O_{3}

which is required to react completely with 25 ml of 0.75 M HCl is:

Q. Calcium carbonate reacts with aqueous

H C I

to give

C a C l_{2}

and

{C O}_{2}

according to the reactions:

C a {C O}_{3 (s)} + 2 H C l_{(a q)} \to C a {C l}_{2 (a q)} + {C O}_{2 (g)} + H_{2} O

What mass of

C a C O_{3}

is required to completely react with

25 m L

0.75 M H C l

Calcium carbonate reacts with aqueous HCl to give CaCl₂ and CO₂ according to the reaction, CaCO₃₍_s₎ + 2 HCl₍_aq₎ → CaCl₂₍_aq₎ + CO₂₍_g) + H₂O₍_l₎

What mass of CaCO₃ is required to react completely with 25 mL of 0.75 M HCl?

Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

Calcium carbonate reacts with aqueous HCl to give CaCl₂and CO₂according to the reaction, CaCO₃+ 2HCl --> CaCl₂+ H₂O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

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Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the raction,CaCO3(s)+2HCl(aq)→CaCl2(aq)+CO2(g)+H2O(l). The mass of CaCO3 is required to react compelety with 25 mL of 0.75 M HCI is:

The correct option is D 0.94 gCaCO3+2HCl(aq)→CaCl2+CO2+H2O n=25×0.751000 Moles of CaCO3 required=25×0.751000×12 Mass of CaCO3=25×0.751000×12×100=0.9375 g

Calcium carbonate reacts with aqueous $H C l$ to give $C a C l_{2} and C O_{2}$ according to the raction, $C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$ .
The mass of $C a C O_{3}$ is required to react compelety with $25$ $mL$ of $0.75 M$ $HCI$ is: