wiz-icon
MyQuestionIcon
MyQuestionIcon
16
You visited us 16 times! Enjoying our articles? Unlock Full Access!
Question

Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the raction,CaCO3(s)+2HCl(aq)CaCl2(aq)+CO2(g)+H2O(l).
The mass of CaCO3 is required to react compelety with 25 mL of 0.75 M HCI is:

A
0.1 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.5 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.5 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.94 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.94 g
CaCO3+2HCl(aq)CaCl2+CO2+H2O
n=25×0.751000

Moles of CaCO3 required=25×0.751000×12
Mass of CaCO3=25×0.751000×12×100=0.9375 g

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Percentage Composition and Molecular Formula
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon