Calcium carbonate reacts with aqueous HCl to give CaCl 2 and CO 2 according to the reaction- -CaCO 3 s -2 HCl a q- CaCl 2a q- CO 2g- H 2 O IWhat mass of CaCO 3 is required to react completely with 25 mL of 0-75 M HCl -

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Standard XII

Chemistry

Depression in Freezing Point

Calcium carbo...

Question

Calcium carbonate reacts with aqueous HCl to give CaCl₂ and CO₂ according to the reaction, CaCO₃₍_s₎ + 2 HCl₍_aq₎ → CaCl₂₍_aq₎ + CO₂₍_g) + H₂O₍_l₎

What mass of CaCO₃ is required to react completely with 25 mL of 0.75 M HCl?

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Solution

0.75 M of HCl ≡ 0.75 mol of HCl are present in 1 L of water

≡ [(0.75 mol) × (36.5 g mol^–1)] HCl is present in 1 L of water

≡ 27.375 g of HCl is present in 1 L of water

Thus, 1000 mL of solution contains 27.375 g of HCl.

Amount of HCl present in 25 mL of solution

= 0.6844 g

From the given chemical equation,

2 mol of HCl (2 × 36.5 = 71 g) react with 1 mol of CaCO₃ (100 g).

Amount of CaCO₃ that will react with 0.6844 g

= 0.9639 g

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Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

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Q. Calcium carbonate reacts with aqueous HCl to give

C a C l_{2}

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Q. Calcium carbonate reacts with aqueous

H C l

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C a C l_{2} and C O_{2}

according to the raction,

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

.
The mass of

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Calcium carbonate reacts with aqueous HCl to give CaCl₂and CO₂according to the reaction, CaCO₃+ 2HCl --> CaCl₂+ H₂O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

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Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3(s) + 2 HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l) What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl?

Calcium carbonate reacts with aqueous HCl to give CaCl₂ and CO₂ according to the reaction, CaCO₃₍_s₎ + 2 HCl₍_aq₎ → CaCl₂₍_aq₎ + CO₂₍_g) + H₂O₍_l₎

What mass of CaCO₃ is required to react completely with 25 mL of 0.75 M HCl?