Question

Calcium imide on hydrolysis gives a gas $B$, which on oxidation by bleaching powder gives a gas $C$. Gas $C$ on reaction with magnesium gives a compound $D$, which on hydrolysis again gives a gas $B$. Hence, $B,C$ and $D$ are respectively:

• A. $N{H}_3,N_2,M{g}_3{N}_2$
• B. $N_2,N{H}_3,MgNH$
• C. $N_2,N_2{O}_5,Mg(N{O}_3{)}_2$
• D. $N{H}_3,N{O}_2,Mg(N{O}_2{)}_2$

Answer 1

The correct option is A $N{H}_3,N_2,M{g}_3{N}_2$

Calcium imide on hydrolysis gives a gas $B$ which on oxidation by bleaching powder gives a gas $C$. Gas $C$ on reaction with magnesium gives a compound $D$, which on hydrolysis again gives a gas $B$. Hence, $B,C$ and $D$ are $N{H}_3,N_2$ and $M{g}_3{N}_2$ respectively.

The reactions are as follows:
$Ca\left(NH\right)+2H_{2}O\to Ca(OH{)}_2+N{H}_3(g)$
$2N{H}_3+3CaOC{l}_2\to N_2\left(g\right)+3CaC{l}_2+3H_{2}O$
$N_2\left(g\right)+3Mg\to M{g}_3{N}_2$
$M{g}_3{N}_2+6H_{2}O\to 3Mg(OH{)}_2+2N{H}_3$