Question

Calculate CFSE values for the following system.

$d^1$ - octahedral.

• A. $-0.4{\Delta }_0$
• B. $0.4{\Delta }_0$
• C. $0.6{\Delta }_0$
• D. $-0.6{\Delta }_0$

Answer 1

The correct option is A $-0.4{\Delta }_0$

Option (A) is correct.

In $d^1$- octahedral, one electron is their in $t_{2g}$.

By applying formula,

$\Delta$ = no. of electrons in $t_{2g}$⋅(−0.4)+ no. of electrons in $e_g$(0.6)

= 1(−0.4)+0(0.6)

= − 0.4${\Delta }_0$