Calculate change in internal energy for 2 moles of an ideal gas that temperature rises from 27∘ C to 127∘ C. [ Given : Cp,m = 13.314 + 0.04 T ]
3800 J
Cv.m=Cp.m−R⇒(13.314−8.314)+0.04T
⇒5+0.04T
△U=n.Cv,m,△T
△U=(T2∫T1(5+0.04T))×2
△U=(5(△T)+0.04(T222−T212))×2
= 3800 J